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A circle is centered about the point (2, 0). The point (0, 1) is on the circle. Which statement proves that the point (4, 1) is also on the circle?

User Dognotdog
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Answer:

Explanation:

the circle is at the origin and (0,4) is a point on the circle then the radius of the circle is:

r^2=0^2+4^2

r^2=16

r=4

so we can check that the other point is four units from the origin and thus also on the circle...

d^2=2^2+6^2

d^2=4+36

d^2=40

since d^2>r^2, (2,6) is outside the circle

User Vasa
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