Question

Rodney bought a 25-pound bag of dog food. His dog ate 10 2/5 pounds of the food in the first month and 10 4/5 pounds of the food in the second month. How much dog food, in pounds, did Rodney's dog eat in total? How much dog food, in pounds, was remaining in the bag at the end of the two months?

Answer 1

Eaten: 21.2

Remaining:
`3(4)/(5)` pounds

Explanation:

Eaten

To find how much was eaten, add the given data together of what the dog at during the number of months given.

`10(2)/(5)+10(4)/(5) =21(1)/(5)`

Step 1: Add the whole numbers

`10 +10=20`

Step 2: Combine fractions

`(2)/(5) + (4)/(5) = (6)/(5)`

Step 3: Add the results together

`=20+(6)/(5)`

Step 4: Convert the improper fractions to mixed numbers

`(6)/(5) = 1(1)/(5)`

Step 5: Now add the results together

`=20+1(1)/(5)`

Step 6: Add the numbers
`20+1=21`

`=21(1)/(5)`

In decimal is 21.2

Remaining

Now that we have found what was eaten, subtract the result we found from the total Rooney bought to find what is remaining.

Step 1: Subtract 21.2 from 25

`\frac{\begin{matrix}\space\space&\textbf{\space\space}&4&\space\space&10\\ \space\space&\textbf{2}&\linethrough{5}&.&\linethrough{0}\\ -&\textbf{2}&1&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{0}&3&.&8\end{matrix}}`

In mixed number is
`3(4)/(5)`

There is
`3(4)/(5)` pounds remaining in the bag at the end of two months.

Answer 2

Rodney's dog ate 21 pounds, because 25 minus the remaining 4 pounds is 21.

4 pounds was remaining.

Explanation:

25 pounds minus 10.20 pounds is 14.80

14.80 pounds minus 10.80 is 4 pounds.

Rodney's dog ate 21 pounds, because 25 minus the remaining 4 pounds is 21.

4 pounds was remaining.