25.0k views
5 votes
A bag contains 6 white marbles, 5 red

marbles, 19 marbles of other colors. Find the probability of choosing a white marble and then a red marble if you replace the first marble before choosing the second marble.

1 Answer

3 votes

Answer:

1/30

Explanation:

6 white marbles

5 red marbles

+ 19 marbles of other colors

-----------------------------------------------

30 marbles in total

First drawing:

p(white) = (number of white marbles)/(total number of marbles)

p(white) = 6/30 = 1/5

Second drawing:

Since the first marble is replaced, there are still 30 marbles in the bag.

p(red) = (number of red marbles)/(total number of marbles)

p(red) = 5/30 = 1/6

The two drawings are independent events, so the overall probability of the two events is the product of the individual probabilities.

p(white then red) = p(white) × p(red)

p(white then red) = 1/5 × 1/6

p(white then red) = 1/30

User Hubert Kunnemeyer
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories