Question

Ball falls so that its distance above ground can be modeled by the equation

s
=
−
16
t
2
+
100
s=−16t
2
+100 , where
s
s is the distance above the ground in feet and
t
t represents time in seconds. According to this model, how many seconds does it take for the ball to hit the ground? Round to the nearest tenth if necessary.

Answer 1

6.25 seconds

At ground level the height of ball is 0, i.e., h=0.

Using zero product property, we get -16t -100

= -16t + 100 + 100s

= -16(t + 6.25) -16(ts + -6.25)

= 6.25s