104k views
4 votes
Topic : Multiple Representations of points

PLEASE HELP ME, am having a hard time with these questions

Topic : Multiple Representations of points PLEASE HELP ME, am having a hard time with-example-1

2 Answers

3 votes

Answer:

See below directions.

Explanation:

The condition
-2\pi<\theta<2\pi means you can get to the point by rotating no more than one revolution in either the positive or negative direction.

See the attached image to see the point
\left(3,\,-(3\pi)/(4)\right). Think about how you get to that point: start at the origin, go right (along the positive x-axis) 3 units, then turn in the negative direction (to your right!) through an angle of
(3\pi)/(4).

Now, go again, starting at the origin, only this time, go 3 units right, then turn through an angle of
-(3\pi)/(4)+2\pi=(5\pi)/(4). In other words, you turn one whole revolution in addition to the
-(3\pi)/(4) angle. Your point can now be described by
\left(3,\,(5\pi)/(4)\right).

Another description can be found by rotating in the opposite direction, so an angle of
(3\pi)/(4) and backing up 3 units -- specify a "radius" of -3. The point is then
\left(-3,\,(3\pi)/(4)\right).

You can also try subtracting one revolution
(2\pi) from the angle, but be careful not to let the angle go outside the interval
-2\pi<\theta<2\pi.

The changes you can try are:

add
2\pi to the angle, leave r alone

subtract
2\pi to the angle, leave r alone

add/subtract
\pi (half a revolution) to the angle, make r the opposite.

Topic : Multiple Representations of points PLEASE HELP ME, am having a hard time with-example-1
User Nishant Bhardwaz
by
8.6k points
3 votes

Answer:

Hmm, want piña colada and Jar Jar Binks cookies? just go to India.

User Sanilunlu
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.