Question

The terminal ray of an angle passes through the point (16,–12). What is the value of sine for this angle?​

Answer 1

-3/5

Explanation:

Given :-

• The terminal ray of an angle passes through the point (16,–12).

And we need to find the value of sine for this angle. Therefore we can say that , Base = 16 units and Perpendicular = 12 units . So Using Pyhthagoras Theorem , we can find hypontenuse.

Using Pythagoras Theorem :-

`:\implies` h² = p² + b²

`:\implies` h² = 16² + 12²

`:\implies` h² = 256 + 144

`:\implies` h² = 400

`:\implies` h = 20 u

Therefore the sine will be :-

`:\implies` sinθ = p/h

`:\implies` sinθ = 12/20

`:\implies` sinθ = 3/5

• And it is in third quadrant so , sine will be negative .

`:\implies` sinθ = -3/5

Therefore the value of sine is -3/5.