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Find the period of y = 2 sin 0-3

Find the period of y = 2 sin 0-3-example-1
User Yehudit
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Answer:

Explanation:

Given :-

  • y = 2 sinθ - 3

And we need to find out the period of it . Now using the form ,


:\implies y = a sin ( bx - c ) + d

On comparing we have ,

  • a = 2
  • b = 1
  • c = 0
  • d = -3

We can find the period using formula ,


:\implies Period = 2π/ |b|


:\implies Period = 2π/|1|


:\implies Period = 2π

Hence the period is 2π .

User Jeff Shannon
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