Question

Find the period of y = 2 sin 0-3

Answer 1

2π

Explanation:

Given :-

• y = 2 sinθ - 3

And we need to find out the period of it . Now using the form ,

`:\implies` y = a sin ( bx - c ) + d

On comparing we have ,

• a = 2
• b = 1
• c = 0
• d = -3

We can find the period using formula ,

`:\implies` Period = 2π/ |b|

`:\implies` Period = 2π/|1|

`:\implies` Period = 2π

Hence the period is 2π .