Answer:
x > 0
Explanation:
Given :-
And we need to find the value of x for which the expression is defined . The expression is ,
√[3x²] ÷ √[4x]
As we can see that x is inside the squareroot. So for defining the expression the value of x should be Greater than 0 . As negative inside the squareroot will give rise to imaginary numbers.
Solution :-
x > 0
In interval notation :-
![:\implies\bf x \in ( 0 , \infty)](https://img.qammunity.org/2022/formulas/mathematics/college/p2gsj6b3v9e4uxst3qma1438k6rrz448ru.png)
Therefore x should be Greater than 0 .