Question

What are the zeroes of the function
nf(x) = x2 + 2x - 35?

Answer 1

`\huge{ \mathfrak{  \underline{ Answer  } \: ✓ }}`

• 
  `{x}^(2) +2 x - 35`

• 
  `{x}^(2) + 7x - 5x - 35`

• 
  `x(x + 7) - 5(x + 7)`

• 
  `(x + 7)(x - 5)`

> Equating with zero

Case - 1

• x + 7 = 0
• x = -7

Case - 2

• x - 5 = 0
• x = 5

The required Zeroes are :

`\huge\boxed{5 \: \: \: and -7}`

_____________________________

`\mathrm{ \#TeeNForeveR}`

Answer 2

x = - 7, x = 5

Explanation:

To find the zeros, let f(x) = 0 , that is

x² + 2x - 35 = 0 ← in standard form

(x + 7)(x - 5) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 7 = 0 ⇒ x = - 7

x - 5 = 0 ⇒ x = 5