Question

A 6.5 liter sample of a gas at 150 degrees C has a pressure of 1.26 atm. If the temperature and pressure increase to 250 degrees C and 3.14 atm, what is the new volume?

Answer 1

3.23 L

Step-by-step explanation:

Using the combined gas law formula as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

T1 = initial temperature (K)

T2 = final temperature (K)

V1 = initial volume (L)

V2 = final volume (L)

According to the provided information in this question;

P1 = 1.26atm

P2 = 3.14atm

V1 = 6.5L

V2 = ?

T1 = 150°C = 150 + 273 = 423K

T2 = 250°C = 250 + 273 = 523K

Using P1V1/T1 = P2V2/T2

1.26 × 6.5/423 = 3.14 × V2/523

8.19/423 = 3.14V2/523

0.0194 = 3.14V2/523

Cross multiply

3.14V2 = 523 × 0.0194

3.14V2 = 10.146

V2 = 10.146/3.14

V2 = 3.23L