Question

Please help me I’m trying to pass

Answer 1

`(16)/(3)`

Explanation:

`h(x) = 3 {x}^(2) - 3 \\ plug \: x = (2)/(3) \\ h \bigg( (2)/(3) \bigg) = 3\bigg( (2)/(3) \bigg) ^(2) - 3 \\ h \bigg( (2)/(3) \bigg) = 3 * (4)/(9) - 3\\ h \bigg( (2)/(3) \bigg) = (4)/(3) - 3 \\ h \bigg( (2)/(3) \bigg) = (4 - 9)/(3) \\ h \bigg( (2)/(3) \bigg) = ( - 5)/(3) \\ \\ h(x) = 3 {x}^(2) - 3 \\ plug \: x = h \bigg( (2)/(3) \bigg) \\ \\ h \bigg(h \bigg( (2)/(3) \bigg) \bigg) = 3.[h \bigg( (2)/(3) \bigg)] ^(2) - 3 \\ = 3. \bigg(( - 5)/(3) \bigg)^(2) - 3 \\ = 3 * (25)/(9) - 3 \\ = (25)/(3) - 3 \\ = (25 - 9)/(3) \\ = (16)/(3)`