Question

Find the vertex and the x- and y- intercept of the following quadratic equations

y = 5x² +15x+10​

Answer 1

Vertex (-3/2, -5/4) x=-2 x=-1 y=10

Answer 2

x int. (-1,0) and (-2,0). y-int,(0,10)

Explanation:

y-int. it's 10 because the y-int is always the c value.

x-int.

x=-b±√b²-4ac/2a

x=-15±√15²-4(5)(10)/2(5)

x=-15±√225-200/10

x=-15±√25/10

x= -15+5/10. x=-15-5/10

x=-10/10. x=-20/10

x=-1. x=-2