40.4k views
10 votes
C

\qquad m \angle AOC
m∠AOC
m, angle, A, O, C
is a straight angle.

m

A
O
B
=
8
x
+
5
1

\qquad m \angle AOB = 8x + 51^\circ
m∠AOB=8x+51

m, angle, A, O, B, equals, 8, x, plus, 51, degrees

m

B
O
C
=
6
x

2
5

\qquad m \angle BOC = 6x - 25^\circ
m∠BOC=6x−25

m, angle, B, O, C, equals, 6, x, minus, 25, degrees
Find
m

A
O
B
m\angle AOB
m∠AOB
m, angle, A, O, B
:

C \qquad m \angle AOC m∠AOC m, angle, A, O, C is a straight angle. m ∠ A O B = 8 x-example-1
User Meanman
by
5.0k points

1 Answer

3 votes

Answer:

  • m∠AOB=139°

Explanation:

m∠AOB+m∠BOC=180°

m∠AOB=8x+51°

m∠BOC=6x-25°

~


\tt 8x+51+6x-25=180


\tt 14x+26=180


\tt 14x=180-26


\tt \cfrac{14x}{14} =\cfrac{154}{14}


\tt x=11

m∠AOB:-


\tt 8(11)+51


\tt =88+51


\tt =139^(o)

Therefore, m∠AOB=139°

User Oleksandr Samsonov
by
4.9k points
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