Answer:
Explanation:
12)
we are told that ∠ABD = 61°
then we also know that ∠ADB = 61° b/c there are the equal legs of an isosceles triangle.
and we know by inspection that the ΔBCD is identical to ΔABD so it also has 61° angles so
∠ABC = 61 + 61 =122°
:)