Question

3. How many moles of NaCl are present in 6000. La 1.5 M NaCl solution?

A.9.0

B.9.0 x 10^3 moles

C.4.0 x 10^8 moles​

Answer 1

Option A (9.0) is the correct alternative.

Step-by-step explanation:

The given values are:

Molarity,

= 1.5 M

Volume,

= 6000 mL

or,

= 6 L

As we know,

⇒
`Molarity=(Moles)/(Volume)`

or,

⇒
`The \ moles \ of \ NaCl=Molarity* Volume`

By putting the values, we get

`=1.5* 6`

`=9 \ mol`