Question

Points A and B lie on a circle with radius 1, and arc AB ⌢ has a length of
`(\pi )/(3)`. What fraction of the circumference of the circle is the length of arc AB ⌢?

Answer 1

L

• Ø/360×2πr

π/3=60°

• L=60/360×2π(1)
• L=1/6×2π
• L=π/3
• L=1.047units

Answer 2

Solution given:

arc AB :angle=
`(\pi )/(3)`=60

radius[r]=1

Now

we have

Circumference the circle is the length of arc AB ⌢:
`(arc AB )/(360)2\pi*r`

:

`(180)/(3) / 360 * 2\pi \: * 1`

=⅓π or 1.047units

Note:

For angle π=180

For length π=
`(22 )/(7)`.