Question

PLEASE HELP QUICK

Using a model of the prototype artillery, a ball is fired into the air with an initial upward velocity of 48 ft/s. Its height, h, in feet after t seconds is given by the function:
What height will the ball be when 2 seconds has passed?
In how many seconds will the ball reach its maximum height?
What is the ball’s maximum height?
After how many seconds will the ball hit the ground?

equation is in the comments!!!!!

Answer 1

t = time Just put t = 2 into the equation and calculate h

h = - 16(2^2) + 48(2) + 4 Got it ?