\sqrt{ {(x - 3)}^(3) } - 64 = 0 ​

Question

`\sqrt{ {(x - 3)}^(3) } - 64 = 0`
​

Answer 1

x = 19

Explanation:

`\sqrt[2]{x-3^3}` = 64

`\sqrt[2]{x-3^3}` = 4³

multiply each side by the exponent 2/3 so the radical sign on left is removed

(
`\sqrt[2]{x-3^3}`)^2/3 = (4³)^2/3

x - 3 = 4²

x - 3 = 16

x = 19