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Where the population standard deviation is known, the test statistic is determined to be -2.5. What is the p-value for this test?

1 Answer

4 votes

Answer:


P(Z<-2.5) =0.0062097

Explanation:

From the question we are told that:

Test statistic t =-2.5

Generally the equation for Test for statistics is mathematically given by


t=(\=x-\mu)/((s)/(√(n) ) )


t=-2.5

Therefore

P-value from Z table is

For left tailed test


P(Z<-2.5) =0.0062097

therefore the P-value for the test is


P(Z<-2.5) =0.0062097

User Rafael Mueller
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