Question

A 17.98-g piece of iron absorbs 2056.5 joules of heat energy, and its temperature changes from 25°C to 200°C. Calculate the specific heat capacity of iron.

Answer 1

Answer:
`0.65\ J/g.^(\circ)C`

Step-by-step explanation:

Given

Mass of iron piece is
`m=17.98\ g`

Heat absorbed
`Q=2056.5\ J`

Temperature changes from
`25^(\circ)C\ to\ 200^(\circ)C` i.e.

`\Delta T=200-25=175^(\circ)C`

Heat absorbed is given by
`Q=mc\Delta T\quad [c=\text{specific heat of material}]`

Insert the values

`\Rightarrow 2056.5=17.98* c* 175\\\\\Rightarrow c=(2056.5)/(3146.5)\\\\\Rightarrow c=0.65\ J/g.^(\circ)C`

Thus, the specific heat of iron is
`0.65\ J/g.^(\circ)C`