1 Answer

Pepuch · Answer 1 · 2022-09-23T12:19:59+0000

Answer:
$1.089* 10^5\ A$

Step-by-step explanation:

Given

Charge discharged
$Q=9.7\C$

time taken
$t=8.9* 10^(-5)\ s$

Current is given as rate of change of discharge i.e.

$\Rightarrow I=(Q)/(t)\\\\\Rightarrow I=(9.7)/(8.9* 10^(-5))\\\\\Rightarrow I=1.089* 10^5\ A$

Therefore, the average current is
$1.089* 10^5\ A$

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