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S + 6 HNO3 → H2SO4 + 6 NO2 + 2 H2O

In the above equation, how many grams of water can be made when 1.1 moles of HNO3 are consumed?

User Unicco
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Answer:


fro \: the \: equation : \\ 6 \: moles \: of \: nitric \: acid \: produce \: 2 \: moles \: of \: water \\ 1.1 \: moles \: of \: nitric \: acid \: react \: with \: ( (1.1)/(6) * 2) \: moles \\ = 0.367 \: moles \: of \: water \\ 1 \: mole \: of \: water \: weighe \: 18 \: g \\ 0.367 \: moles \: will \: weigh \: ( 0.367 * 18) \: g \\ = 6.6 \: g \: of \: water

User Marko Taht
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