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A conducting bar moves along a circuit with a constant velocity. A constant magnetic field of 1.23 T is perpendicular to the bar and circuit. The bar covers 2.00 m2 of area in 1…

A conducting bar moves along a circuit with a constant velocity. A constant magnetic field of 1.23 T is perpendicular to the bar and circuit. The bar covers 2.00 m2 of area in 1…
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A conducting bar moves along a circuit with a

constant velocity. A constant magnetic field of
1.23 T is perpendicular to the bar and circuit.
The bar covers 2.00 m2 of area in
1.00 second. What is the EMF
induced in the circuit?
[?] V

User Don Ho
by
7.5k points

2 Answers

1 vote

Answer:

2.46

Step-by-step explanation:

acellus

User Lewis Weng
by
9.4k points
0 votes

Step-by-step explanation:


E = (BA)/(t) \sin( \theta) \\ = (1.23 * 2)/(1) \\ = 2.46 \: V

User Lord Nighton
by
8.5k points
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