Question

A fertilizer has the analysis of 12-24-20. How many pounds of N, P, and K are there in the 3000 lbs. of fertilizer?

Answer 1

`W_N=642.857ibs`

`W_P=1285.714ibs`

`W_K=1071.43ibs`

Explanation:

From the question we are told that:

Ratio of NPK
`R=12-24-20.`

Weight
`W=3000 lbs`

Generally the sum of the ratio is given as

`\sum R=12+24+20`

`\sum R=56`

Generally the Weight of N is mathematically given by

`W_N=(12)/(56)*3000`

`W_N=642.857ibs`

Generally the Weight of P is mathematically given by

`W_P=(24)/(56)*3000`

`W_P=1285.714ibs`

Generally the Weight of K is mathematically given by

`W_K=(20)/(56)*3000`

`W_K=1071.43ibs`