Question

A lamp is connected to the power supply.

The lamp requires an input potential difference of 5.0V

The alternator generates a potential difference of 1.5V

The primary coil of the transformer has 150 turns.

Calculate the number of turns needed on the secondary coil


Number of turns on the secondary coil = ?

Answer 1

There are 45 turns in the secondary coil.

Step-by-step explanation:

Given that,

Input potential of the lamp,
`V_(in)=5\ V`

The output potential of the lamp,
`V_(out)=1.5\ V`

Number of turns in primary coil,
`N_P=150`

We need to find the number of turns needed on the secondary coil. We know that the ratio for a transformer is as follows :

`(V_(out))/(V_(in))=(N_s)/(N_P)\\\\N_s=(V_(out)N_P)/(V_(in))\\\\N_s=(1.5* 150)/(5)\\\\N_s=45\`

So, there are 45 turns in the secondary coil.