Question

7. If mBY
= 41°, what is m YAC? The figure is not drawn to scale. (1 point)

Answer 1

`\\ \sf\longmapsto m<BOY=41°`

We know

`\\ \sf\longmapsto m<BOY=2m<{BAY}`

`\\ \sf\longmapsto m<BAY=41/2=20.5°`

Now

`\\ \sf\longmapsto 20.5°+m<YAC=90°`

`\\ \sf\longmapsto m<YAC=90-20.5=69.5°`

Answer 2

c. ∡YAC=69.5°

Answer:

solution given:

arc m BY=41°

it is a central angle,

its inscribed angle is half of its=41/2=20.5°

we know that

tangent in the circle is perpendicular to the center,so

∡BAC=90°

∡BAY+∡YAC=90°

20.5°+∡YAC=90°

∡YAC=90°-20.5°

∡YAC=69.5°

Explanation: