Question

If you start with 6 moles of N2 and 6 moles of H2 (meaning you won't have enough of 1 of the ingredients), how many moles of NH3 would you be able to make?

Answer 1

`4molNH_3`

Step-by-step explanation:

Hello there!

In this case, according to the given information it will be firstly necessary to set up the chemical equation taking place:

`N_2+3H_3\rightarrow 2NH_3`

We infer we need to calculate the moles of NH3 by using both of the moles of N2 and H2 at the beginning, in order to identify the limiting reactant:

`n_(NH_3)=6molN_2*(2molNH_3)/(1molN_2)=12molNH_3\\\\ n_(NH_3)=6molH_2*(2molNH_3)/(3molH_2)=4molNH_3\\`

Thus, since hydrogen yields the fewest moles of ammonia, we conclude that we are just able to yield 4 moles of NH3.

Regards!