Question

What is the equation of the line that passes through the point (-4, 2) and has a slope of -5/4?​

Answer 1

y = -5/4 x - 3 is the slope-intercept form

5x + 4y = -12 is the standard form

Explanation:

Use the point-slope form:
`y - y_(1) = m(x - x_(1))`

`(x_(1), y_(1))` = (-4, 2)

y - 2 = -5/4(x + 4) Multiply by 4 to remove the fraction

4y - 8 = -5(x + 4)

4y - 8 = -5x - 20

4y = -5x - 12

y = -5/4 x - 3 is the slope-intercept form

5x + 4y = -12 is the standard form