Question

Please help!!!!!!!!

3x2 + x - 4 = 0

SELECT ALL THAT APPLY.



(x - 1)(3x + 4) = 0
(3x +2)(x - 6) = 0
(3x + 4)(x - 1) = 0
(x + 1)(3x - 4) = 0
(3x - 3)(3x - 4) = 0
(3x - 4)(x + 1) = 0

Answer 1

(3x + 4)(x-1)=0

Explanation:

It's a quadratic equation.

now you need to find two numbers such that when you multiply then you get -12 and when you add them you get +1

`3x {}^(2) + x - 4 \\ 3x {}^(2) + 4x - 3x - 4 \\ x(3x + 4) - 1(3x + 4) \\ (3x + 4)(x - 1)`

Answer 2

all of the apply my math teacher always did that and all of them aways applied