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What is the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm?

User Ruslan Bes
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1 Answer

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Answer: The new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

Step-by-step explanation:

Given:
V_(1) = 61 L,
T_(1) = 183 K,
P_(1) = 0.60 atm

At STP, the value of pressure is 1 atm and temperature is 273.15 K.

Now, formula used to calculate the new volume is as follows.


(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))

Substitute the values into above formula as follows.


(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))\\(0.60 atm * 61 L)/(183 K) = (1 atm * V_(2))/(273.15 K)\\V_(2) = 54.63 L

Thus, we can conclude that the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

User Manjula Sridhar
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