Answer:
See below
Explanation:
ΔABC has been flipped over, so we have a reflexion using line BC
So, the answer to 1. is line BC
The result is ΔE'F'D'
Now ΔE'F'D' is moved 4 units to the right. That is the answer to 2.
The result is ΔE"F"D"
Finally ΔE"F"D" is moved 1 unit down. That is the answer to 3.
The final result is ΔEFD
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