Question

At what temperature, in Celsius, will 88.0 g of Ne exert a pressure of 350. kPa in a

48.5 L container? NOTE: You must show your calculation on the attached scratch
paper, including which of the Gas Law formulas you used. *

Answer 1

191 °C

Step-by-step explanation:

We'll begin by calculating the number of mole in 88.0 g of Ne. This can be obtained as follow;

Mass of Ne = 88.0 g

Molar mass of Ne = 20 g/mol

Mole of Ne =?

Mole = mass /molar mass

Mole of Ne = 88 / 20

Mole of Ne = 4.4 moles

Next, we shall determine the temperature. This can be obtained as follow:

Mole of Ne = 4.4 moles

Pressure (P) = 350 KPa

Volume (V) = 48.5 L

Gas constant (R) = 8.314 KPa.L/Kmol

Temperature (T) =?

PV = nRT

350 × 48.5 = 4.4 × 8.314 × T

16975 = 36.5816 × T

Divide both side by 36.5816

T = 16975 / 36.5816

T = 464 K

Finally, we shall convert 464 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 464 K

T(°C) = 464 – 273

T(°C) = 191 °C

Thus, the temperature is 191 °C