Question

Amal designed a silver necklace pendant in the shape of a cone. The slant height of the cone is 5 millimeters, and the radius of the cone is 3 millimeters.

What is the volume of the silver pendant, rounded to the nearest tenth?

Use 3.14 for π.

Answer 1

Answer:37.7

mm3

Explanation:

Answer 2

37.7 mm³

Explanation:

Step 1

We find the height of the cone

we are given slant height = 5mm and radius = 3mm

Height = √l² - r²

Where l = Slant height

Hence

h = √5² - 3²

h = √25 - 9

h = √16

h = 4

Hence, the height of the cone = 4mm

Step 2

We can proceed to calculate the volume of the cone

Volume = 1/3 πr²h

π = 3.14

Hence,

Volume = 1/3 × 3.14 × 3² × 4

= 37.68 mm³

Approximately, Volume of the cone to the nearest tenth = 37.7 mm³