Question

As an airplane rises. the outside temperature drops from 3.6F for every 1000 feet of elevation gain. Suppose the outside temperature is 75F on the ground when the plane takes off and -51F at cruising altitude. How high is the plane then?

1. Write an equation

2.Solve using the equation

Answer 1

35,000

Explanation:

1. Find the difference between 75 and -51.

75 - (-51) = 75+51 = 126

2. Divide 126 by 3.6

126/3.6 = 35

3. Now what is the number 35? That is how much times the airplane has approached 1,000ft. So you have to multiply 35 and 1,000.

35 x 1,000 = 35,000.

4. Find the equation

([75 - x]/3.6) × 1,000, in which this case, x is the Fahrenheit the surroundings is in

a. Substitute x with -51.

b. The equation should follow the exact steps I mentioned earlier.

Hope this helps