Answer:
93.50
(853.90 ; 1040.90)
Explanation:
Mean, xbar = 947.4 mg
Sample size, n = 18
σ = 188
Margin of Error :
Tcritical * σ/√n
TCritical at 95% , df = n - 1 = 17 = 2.11
Margin of Error = 2.11 * 188/√18 = 93.50
The 95%, confidence interval :
Xbar ±Margin of error
Lower boundary = Xbar - margin of error
Lower boundary = 947.4 - 93.50 = 853.90
Upper boundary = Xbar + margin of error
Lower boundary = 947.4 + 93.50 = 1040.90
(853.90 ; 1040.90)