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if 67.8 moles of gas was measured out into a helium balloon how many molecules would be present within the balloon

1 Answer

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Answer:


4.08x10^(25) molecules

Step-by-step explanation:

Hello there!

In this case, since the understanding of the mole-molecules relationships is analyzed via the Avogadro's number:


1mol=6.022x10^(23)molecules

Next, we can solve the following setup by starting with the 67.8 moles of helium and obtaining the required molecules as follows:


67.8mol*(6.022x10^(23)molecules)/(1mol)\\\\=4.08x10^(25) molecules

Best regards!

User Raymond Chiu
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