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How many moles of nitrogen gas will occupy a volume of 5L at 3.85 atm and 27c?

1 Answer

7 votes

Answer:


n=0.78mol

Step-by-step explanation:

Hello there!

In this case, according to the given information, it possible for us to realize that this problem is solved via the ideal gas equation:


PV=nRT

By which we solve for n (moles) as shown below:


n=(PV)/(RT)

Then, we plug in the given pressure, volume and temperature (in K) to obtain:


n=(3.85atm*5L)/(0.08206(atm*L)/(mol*K)*(273+27)K) \\\\n=0.78mol

Regards!

User Gijs Brandsma
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