Answer:
The correct answer is a) 5′-CCA-3′.
Step-by-step explanation:
It is given that in the given mRNA sequence there is a stop codon for the protein it forms, the sequence from the 3' end of mRNA is -
5'-.....CCGUUACCAGGCCUCAUUAUUGGUAACGGAAAAAAAAAAAAAA-3'
Making triplet codes from 3' end -
5'-....CC GUU ACC AGG CCU CAU UAU UGG UAA CGG AAA AAA AAA AAA AAA-3'
In this UAA is the stop codon and 5'-UGG-3' is the codon adjacent to stop codon UAA in the mRNA sequence which will be present at P-site in the mRNA sequence so the anticodon will be the corresponding anticodon for 5'-UGG-3' is 3'-ACC-5' or simply 5'-CCA-3'.