Question

The average kinetic energy of water at 25oC is

Answer 1

Answer: The average kinetic energy of water at
`25^(o)C` is
`1.233 * 10^(-26) J`.

Step-by-step explanation:

Given: Temperature =
`25^(o)C = (25 + 273) K = 298 K`

Kinetic energy is the energy acquired by the molecules of a substance due to its motion.

Formula to calculate average kinetic energy is as follows.

`K.E = (3)/(2)kT`

where,

T = temperature

k = Boltzmann constant =
`1.38 * 10^(-23) J/K`

Substitute the value into above formula as follows.

`K.E = (3)/(2)kT\\= (3)/(2) * 1.38 * 10^(-23) J/K * 298 K \\= 1.233 * 10^(-26) J`

Thus, we can conclude that the average kinetic energy of water at
`25^(o)C` is
`1.233 * 10^(-26) J`.