62.2k views
1 vote
Como resuelvo esta inecuació 2x + 8 ≥ 20?

User Cecchi
by
4.7k points

1 Answer

3 votes


\huge\text{Hey there!}



\mathsf{2x + 8 \geq 20}


\large\textbf{Subtract 8 to both sides}


\mathsf{2x + 8 - 8 \geq 20 - 8}


\large\textbf{Simplify it}


\mathsf{2x \geq 12}


\large\textbf{Divide 2 both sides}


\mathsf{(2x)/(2) \geq (12)/(2)}


\large\textbf{Simplify it}


\mathsf{x \geq (12)/(2)}


\mathsf{x \geq 6}


\large\textbf{It is a CLOSED circle shaded to the right.}



\huge\text{Therefore your answer should be:}


\huge\boxed{\mathsf{x \geq 6}}\huge\checkmark




\huge\text{Good luck on your assignment \& enjoy your day\bf !}



~
\frak{Amphitrite1040:)}

User Cachius
by
5.1k points