Question

A current of 2.50 amps is passed through an electrolytic cell containing a solution of M(NO3)2, where M represents an unidentified metal. The only reaction that occurs at the cathode is the deposition of the unknown metal. After 2.00 hours, 5.93 g of the metal has been deposited.

Required:
Determine the chemical symbol of the metal.

Answer 1

The chemical symbol will be "
`_(29)^(63.5)\textrm{Cu}`".

Step-by-step explanation:

The given values are:

Current,

I = 2.50 amps

Time,

t = 2 hr

or,

= 7200 sec

Metal deposited,

W = 5.93 gm

As we know,

⇒
`W=Z* i* t`

or,

⇒
`Z=(W)/(i* t)`

On putting the given values, we get

⇒
`=(5.93)/(2.5* 7200)`

⇒
`=3.2945* 10^(-4)`

hence,

⇒
`Atomic \ mass=Z* electrons* 96500`

⇒
`=3.2945* 10^(-4)* 2* 96500`

⇒
`=63.5`

Thus the above is the right answer.