Four equivalent forms of a quadratic function are given. Which form displays the zeros of function h?

Question

asked Mar 24, 2022 1.1k views

1 Answer

Arun Palanisamy · Answer 1 · 2022-03-30T20:14:58+0000

Answer:

h(x) = -4(x - 2)(x + 2)

Explanation:

Given

h(x) = -4(x - 2)(x + 2)

h(x) = -2(2x^2 - 8)

h(x) = -4(x^2 - 4)

h(x) = -4x^2 + 16

Required

Which shows the zeros of h(x)

To determine the zeros of a function, the function must be written as:

$h(x) = n(x \± a)(x \± b)$

Where

$n \\e 0$

$\± a,\± b$ are the zeros

Of options (a) to (d), only (a) is written in the form:

$h(x) = n(x \± a)(x \± b)$

i.e.

h(x) = -4(x - 2)(x + 2)

Other options do not show the zeros