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Tom Fakes · Answer 1 · 2022-07-19T17:50:53+0000

Answer:
$49.7\ cm^3$

Step-by-step explanation:

Given

At temperature
$T_1=289\ K$

Volume is
$V_1=42\ cm^3$

and the temperature changes to
$T_2=342\ K$

At this temperature volume is
V_2

Consider Pressure remains the constant

$\therefore (V_1)/(T_1)=(V_2)/(T_2)\\\\\Rightarrow V_2=V_1* (T_2)/(T_1)\\\\\text{Insert values}\\\\\Rightarrow V_2=42* (342)/(289)\\\\\Rightarrow V_2=49.7\ cm^3$

The volume at this temperature is
$49.7\ cm^3$

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