Answer:
In 2012 the population of the city reach 457 thousand.
Explanation:
We are given with equation A= 265
![e^(0.039t)](https://img.qammunity.org/2022/formulas/mathematics/high-school/a9iss04uoewg0vopdyc2shd28p4s0jhd52.png)
Here it is given that A is 457.
So, plug in A as 457 and solve for 't'.
457= 265
![e^(0.039t)](https://img.qammunity.org/2022/formulas/mathematics/high-school/a9iss04uoewg0vopdyc2shd28p4s0jhd52.png)
Divide both sides by 265.
1.7245283 =
![e^(0.039t)](https://img.qammunity.org/2022/formulas/mathematics/high-school/a9iss04uoewg0vopdyc2shd28p4s0jhd52.png)
Now, take natural log on both sides,
ln(1.7245283)= ln(
)
0.5449535= 0.039t
Divide both sides by 0.039
t=13.97...
So, 't' is years after 1998.
So, 1998+13.97 =2011.97...
If we round to nearest years, we do get 2012.