Question

When 3.20 moles of magnesium is heated and placed in a container of nitrogen gas the two substances undergo a synthesis reaction. How many moles of nitrogen gas will react? 3 Mg (s) + 1 N2 (g) → 1 Mg3N2 (s)

Answer 1

1.06 moles of nitrogen gas will react with 3.20 moles of magnesium in the container.

Step-by-step explanation:

`3 Mg (s) + 1 N_2 (g) \rightarrow 1 Mg_3N_2 (s)`

Moles of magnesium heated = 3.20 mol

According to reaction, 3 moles of magnesium reacts with 1 mole of nitrogen gas, then 3.20 moles of magnesium will react with:

`=(1)/(3)* 3.20 mol=1.07 \text{ mol of }N_2`

1.06 moles of nitrogen gas will react with 3.20 moles of magnesium in the container.