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Find the equation of the tangent to the curve


y = (4)/(x)
at

(8. (1)/(2) )


1 Answer

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Answer:

y = -x/16 +1

Explanation:

The slope is at any point x is ...

y' = -4/x^2

so, at x=8, the slope is ...

m = -4/8^2 = -4/64 = -1/16

The point-slope form of the equation of the line is ...

y -k = m(x -h) . . . . . . . line with slope m through point (h, k)

Then the line with slope -1/16 through point (8, 1/2) is ...

y - 1/2 = -1/16(x -8)

y = -1/16x +1/2 + 1/2 . . . . . eliminate parentheses, add 1/2

y = -1/16x +1 . . . . . equation of the tangent line

Find the equation of the tangent to the curve y = (4)/(x) at (8. (1)/(2) ) ​-example-1
User Libi
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