Question

Solve each system by substitution 2x + y = 20 and 6x - 5y = 12

Answer 1

`\huge\mathbf{Answer࿐}`

`\underline{ \underline{ \bf{step} - 1}}`

Taking first equation,

• 
  `2x + y = 20`

• 
  `y = 20 - 2x`

`\underline{ \underline{ \bf{step} - 2}}`

plugging the value of y in second equation,

• 
  `6x - 5y = 12`

• 
  `6x - 5(20 - 2x) = 12`

• 
  `6x - 100 + 10x = 12`

• 
  `16x = 12 + 100`

• 
  `x = (112)/(16)`

• 
  `x = 7`

`\underline{ \underline{ \bf{step} -3}}`

plugging the value of x in first equation,

• 
  `2x + y = 20`

• 
  `(2 * 7) + y = 20`

• 
  `14 + y = 20`

• 
  `y = 20 - 14`

• 
  `y = 6`

Conclusion :

• 
  `x = 7`
• 
  `y = 6`

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`\mathrm{ \#TeeNForeveR}`