Question

Need help with this question I would appreciate it.​

Answer 1

`\huge\boxed{x \geq (10b)/(b-a) }`

Explanation:

`\displaystyle b(x-3) \geq ax+7b\\\\bx -3b\geq ax+7b\\\\Subtract \ ax \ to \ both \ sides\\\\bx-ax-3b\geq 7b\\\\Add \ 3b \ to \ both \ sides\\\\bx-ax \geq 7b+3b\\\\x(b-a) \geq 10b\\\\Divide \ (b-a) \ to \ both \ sides\\\\x \geq (10b)/(b-a) \\\\\rule[225]{225}{2}`

Hope this helped!

~AH1807