Question

A gas has a pressure of 0.370 atm at 30,0 °C. What is the pressure at standard temperature?

(assume constant volume)

Answer 1

0.333 atm

Step-by-step explanation:

Step 1: Given data

• Initial pressure (P₁): 0.370 atm

• Initial temperature (T₁): 30.0 °C

• Final pressure (P₂): ?

• Final temperature (T₂): 273.15 K (standard temperature)

Step 2: Convert 30.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 30.0 + 273.15 = 303.2 K

Step 3: Calculate the final pressure of the gas

If we assume ideal behavior and constant volume, we can calculate the final pressure od the gas using Gay-Lussac's law.

P₁/T₁ = P₂/T₂

P₂ = P₁ × T₂/T₁

P₂ = 0.370 atm × 273.15 K/303.2 K = 0.333 atm