Given:
A square base pyramid with base length 6 cm and the slant height is 4 cm.
To find:
The lateral surface area of the given square pyramid.
Solution:
The lateral surface area of the given square pyramid is equal to the areas of 4 congruent triangles with base 6 cm and height 4 cm.
Area of a triangle is:
So, the area of one triangle or one side of the given pyramid is:
Now, the lateral surface area of the given square pyramid is 4 times the area of one triangle.
Therefore, the lateral surface area of the given square pyramid is 48 cm².